9x^2-170x+625=0

Solution for 9x^2-170x+625=0 equation:

9x^2-170x+625=0

a = 9; b = -170; c = +625;
Δ = b2-4ac
Δ = -1702-4·9·625
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-170)-80}{2*9}=\frac{90}{18}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-170)+80}{2*9}=\frac{250}{18}
=13+8/9
$